How many grams of KNO3 should be used to prepare 2.00 L of a 0.500 M solution?

Answer 1

Looking at answers and explanation to your previous questions...

volume = 2 liters

moles/liter = 0.500 = 0.500 M

Total moles = 0.500 mol/L x 2 L = 1.00 moles

grams = 1.00 moles KNO3 x molar mass KNO3 = grams KNO3