J.R. S. answered 02/03/20
Ph.D. University Professor with 10+ years Tutoring Experience
Comparing expts 1&2 ... zero order in A b/c doubling A has no effect on rate
Comparing expts 2&3 ... 2nd order in B b/c doubling B results in a rate increase of 4x
Comparing expts 3&4 ... 1st order in C b/c increasing B by 1.5 times and Reducing C in half changes rate by 1.125 which is expected if rate is directly related to [C], ie is 1st order in C
Rate = k[B]2[C]
Using expt 1:
rate = 0.002 M/s
[B] = 0.2 M
[C] = 0.4 M
k = 0.002 Ms-1/(0.2 M)2(0.4M)
k = 0.125 M-2s-1