Jasmine G.

asked • 01/25/20

1) sec(40-8\deg )\cos (60-18\deg )=1 .2) cos(40-10\deg )=(1)/(sec(60-26\deg ))

find the least positive value of theta (the 0 with the line in it) for both . PLEASE EXPLAIN i do not understand it.

Joseph D.

tutor
Hi Jasmine G., I don't understand what you have written. What is sec(40-8/deg) and all the other trig functions?
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01/25/20

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