During an experiment to determine the heat of a reaction, 590 g of water in a calorimeter increased in temperature from 18° C to 28°C. What is the approximate number of kJ given off by the reaction?

Question

The partial answer is:2X kJ

Answer 1

Once again.... q = mC∆T

q = heat = ?

m = mass = 590 g

C = specific heat = 4.184 J/g/deg

∆T = change in temperature = 28º - 18º = 10º

q = (590 g)(4.184 J/g/deg)(10 deg) = 24,686 J = 24.866 kJ = 25 kJ