J.R. S. answered 01/24/20
Ph.D. University Professor with 10+ years Tutoring Experience
CH4(g) + 3 Cl2(g) ==> CHCl3(g) + 3 HCl(g) ... balanced equation
Using dimensional analysis:
52.0 g CHCl3 x 1 mol CHCl3/119.38 g = 0.4356 moles CHCl3 produced
0.4356 moles CHCl3 x 1 mol CH4 / 1 mol CHCl3 = 0.4356 moles CH4 required
grams CH4 required = 0.4356 mols CH4 x 16.04 g/mole = 6.99 g CH4 needed