J.R. S. answered 01/22/20
Ph.D. University Professor with 10+ years Tutoring Experience
Cl2 + H2 ==> 2HCl ... balanced equation
Find moles H2 being used:
PV = nRT
n = PV/RT = (1.13 atm)(3.450 L)/(0.0821 Latm/Kmol)(298K)
n = 0.159 moles H2 being used
Assuming Cl2 is not limiting, then you have...
0.159 mols H2 x 2 mol HCl/mol H2 x 36.5 g HCl/mol HCl = 11.6 g HCl