How many Liters of carbon dioxide gas will be produced when 75.0g of calcium carbonate are decomposed into calcium oxide at room temperature (22.0C) and room pressure (1.00 atm)?

Answer 1

CaCO₃ ==> CaO + CO₂ ... balanced equation

75.0 g CaCO₃ x 1 mol/100 g = 0.750 moles CaCO₃

0.750 mol CaCO₃ x 1 mol CO₂/CaCO₃ = 0.750 moles CO₂

PV = nRT

V = nRT/P = (0.750)(0.0821)(295)/1 = 18.2 liters