
William W. answered 01/16/20
Experienced Tutor and Retired Engineer
If f "(x) = 20x3 + 12x2 + 4, then by taking the anti-derivative we can find that f'(x) = 5x4 + 4x3 + 4x + C1 and we can again take the anti-derivative of f'(x) to find that f(x) = x5 + x4 + 2x2 + C1x + C2
We can now use f(0) to say:
f(0) = 1 = (0)5 + (0)4 + 2(0)2 + C1(0) + C2 to find that C2 = 1
We can then plug that into the f(x) equation we have and use f(1) to calculate C1 like this:
f(1) = 3 = (1)5 + (1)4 + 2(1)2 + C1(1) + 1
3 = 1 + 1 + 2 + C1 + 1
3 = 5 + C1
C1 = -2
So f(x) = x5 + x4 + 2x2 - 2x + 1