J.R. S. answered 01/15/20
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = ?
m = mass of water = 370 g
C = specific heat of water = 1 cal/g/deg
∆T = change in temperature = 38.8º - 22.7º = 16.1º
q = (370 g)(1 cal/g/deg)(16.1 deg) = 5957 cal <-- this is the heat released from 0.66 g of olive oil.
Heat released from 1 g of olive oil = 5957 cal/0.66 g = 9026 cal/g
Converting to kcal/g: 9026 cal/g x 1 kcal/1000 cal = 9.026 kcal/g = 9.0 kcal/g (to 2 significant figures)