What will the stopping distance be for a 3000-kg care if -3000 N of force are applied when the car is traveling 10m/s

Question

I need to know how to solve the above problem?

Answer 1

Use the kinematic relation

v² - v₀² = 2ad

v = final speed = 0 (full stop)

v₀ = initial speed = 10 m/s (given)

a = acceleration = F/m = (-3000 N)/(3000 kg) = -1 m/s²

d = stopping distance = ?

With the given quantities,

d = -v₀² / (2a) = -(10)² / [2(-1)] meters = 50 meters