How to balance this redox reaction equation?

Question

HNO₃ (aq) + KI (aq) ---> KNO₃ (aq) + I₂ (s) + NO (g) + H₂0 (l)

Answer 1

I^- ===> I₂ oxidation half reaction

2I^- ===> I₂ to balance Iodine

2I^- ===> I₂ + 2e- to balance charge

NO₃^- ==> NO reduction half reaction

NO₃^- ==> NO + 2H₂O to balance oxygen

NO₃^- + 4H⁺ ==> NO + 2H₂O to balance hydrogen using acid media

NO₃^- + 4H⁺ + 3e- ==> NO + 2H₂O to balance charge

Multiply oxidation reaction by 3 and reduction reaction by 2 to equalize the electrons:

6I^- ==> 3I₂ + 6e-

2NO₃ + 8H⁺ + 6e- ==> 2NO + 4H₂O and adding these together we get...

6I^- + 2NO₃^- + 8H⁺ ==> 3I₂ + 2NO + 4H₂O and adding back spectator ions we end up with...

6KI + 8HNO₃ ==> 6KNO₃ + 2NO + 3I₂ + 4H₂O