Mark M. answered 01/10/20
Tutor
5.0
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Mathematics Teacher - NCLB Highly Qualified
tan θ + √3 = 0
tan θ = -√3
tan π/3 = √3
tan < 0 in QII and QIV.
θ ∈ {2π/3, 5π/3)
Mark M. answered 01/10/20
Mathematics Teacher - NCLB Highly Qualified
tan θ + √3 = 0
tan θ = -√3
tan π/3 = √3
tan < 0 in QII and QIV.
θ ∈ {2π/3, 5π/3)
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