How many moles of oxygen atoms are present in 4.39 mol diphosphorus pentoxide (P2O5)?

Question

How many moles of oxygen atoms are present in 4.39 mol diphosphorus pentoxide (P₂O₅)?

Answer 1

4.39 mol P₂O₅ x 5 mol O atoms/mol P₂O₅ = moles O atoms

Answer 2

Each molecule of Diphosphours Pentoxide has 5 of oxygen atoms (the subscript). That means that one mole of Diphosphorus Pentoxide will have five moles of oxygen atoms.

Now you have a conversion factor. 1 mole of P₂O₅ = 5 moles O atoms.... so

4.39 mol P₂O₅ would be equivalent to 4.39 x 5 moles O atoms = 21.95 moles of O atoms