find the value of x perimeter of triangle abc=96 3x+2 4x+1 2x

Answer 1

I am guessing that (3x + 2), (4x + 1) and (2x) are all sides of triangle ABC.

To find perimeter, we add up all of the sides. For this problem, we know what the perimeter is, so we can set that sum equal to 96. So we write:

3x + 2 + 4x + 1 + 2x = 96

Combine like terms:

9x + 3 = 96

Solve for x. When solving, reverse the order of operations, PEMDAS. With PEMDAS, addition and subtraction come last, but when solving, you do those operations first.

Subtract 3 from both sides:

9x = 93

Divide both sides by 9:

x = 93/9.

Answer 2

So I am assuming that the perimeter of the triangle is 96? And the sides are as follows:

Side a: 3x+2

Side b: 4x+1

Side c: 2x

I hope I am understanding correctly.

Perimeter is the continuous line formed around an enclosed figure. So for a triangle, the perimeter is:

P = a + b + c

We know that P = 96 and we have functions for a, b and c so lets add them up:

96 = (3x+2) + (4x+1) + 2x

Next we simply by adding like terms (adding x's with x's and constants with constants)

96 = 9x + 3

Subtract 3 from both sides

93 = 9x

Divide both sides by 9

10.333 = x

If you want to check your answer we can plug this x back into the sides and add them up:

Side A = 3x+2 If x = 10 and 1/3 then side A = 33

Side B = 4x+1 if x = 10 and 1/3 then side B = 127/3

Side C = 2x if x = 10 and 1/3 then side C = 62/3

Add 33 + 124/3 +62/3 = 288 /3 = 96 It works!