how many grams of potassium chlorate must react to form 50 grams of potassium chloride? The other product of the reaction is oxygen gas.

Answer 1

Potassium chlorate = KClO₃

potassium chloride = KCl

The reaction of interest is 2KClO₃ ==> 2KCl + 3O₂ ... balanced equation

50 g KCl x 1 mole KCl/74.5 g = 0.671 moles KCl

moles KClO₃ needed = 0.671 moles KCl x 2 mole KClO₃/2 moles KCl = 0.671 moles KClO₃ needed

mass KClO₃ needed = 0.671 moles KClO₃ x 122.6 g/mole = 82.28 g = 82 g KClO₃ needed