
William W. answered 01/03/20
Experienced Tutor and Retired Engineer
If "the particle is moving to the right" then the velocity will be positive (a zero velocity means the object isn't moving and a negative velocity means its moving left).
The velocity is the derivative of position with respect to time. So, taking the derivative, we get s'(t) = t2 - 12t + 36 or, factoring, s'(t) = (t - 6)2 which is positive for all values of t except it is zero for t = 6. So, in reality, none of the answers is correct but answer 4 is the closest (and is OK if you ignore the fact that it slows to a stop at t = 6 then speeds up again after that.