
William W. answered 01/03/20
Experienced Tutor and Retired Engineer
The velocity is the first derivative [s'(t)] and the acceleration is the second derivative [s''(t)].
s'(t) = 2t + 3
so s'(4) = 2(4) + 3 = 11
s''(t) = 2
so s''(4) = 2
Madison C.
asked 01/03/20Given the position function s(t), s(t) = t2 + 3t + 1, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 4 seconds.
Options:
William W. answered 01/03/20
Experienced Tutor and Retired Engineer
The velocity is the first derivative [s'(t)] and the acceleration is the second derivative [s''(t)].
s'(t) = 2t + 3
so s'(4) = 2(4) + 3 = 11
s''(t) = 2
so s''(4) = 2
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