
Mark H. answered 01/03/20
Tutoring in Math and Science at all levels
s(t) = t2 + 3t + 1
velocity is the 1st derivative of position, and acceleration is the 2nd derivative.
velocity: v = s' = 2t + 3. At t = 4, v = 11
acceleration: a = 2
Madison C.
asked 01/03/20Given the position function s(t), s(t) = t2 + 3t + 1, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 4 seconds
Options:
Mark H. answered 01/03/20
Tutoring in Math and Science at all levels
s(t) = t2 + 3t + 1
velocity is the 1st derivative of position, and acceleration is the 2nd derivative.
velocity: v = s' = 2t + 3. At t = 4, v = 11
acceleration: a = 2
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