Inactive Tutor answered 01/02/20
Tutor
New to Wyzant
y = 3cos(x) + sec(x)
dy/dx = (3cos(x) + sec(x))'
= 3(cos(x))' + (sec(x))'
= 3(-sin(x)) + sec(x)tan(x)
= -3sin(x) + sec(x)tan(x)
Mae S.
asked 01/02/20Find
for y = 3cos(x) + sec(x).
Options:
Inactive Tutor answered 01/02/20
y = 3cos(x) + sec(x)
dy/dx = (3cos(x) + sec(x))'
= 3(cos(x))' + (sec(x))'
= 3(-sin(x)) + sec(x)tan(x)
= -3sin(x) + sec(x)tan(x)
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Mae S.
Thank you!01/02/20