J.R. S. answered • 12/28/19
Ph.D. University Professor with 10+ years Tutoring Experience
It is assumed for the purpose of answering this question that the KOH is aqueous. Also, I have no idea what is meant by (D) solid suphate solution. How does one have a solid solution? Perhaps that was meant to read sodium sulphate solution. If so, then it would not react with aqueous KOH.
(C) solid ammonium chloride will not react with KOH(aq) because it will dissolve in the aqueous phase and then the NH4+ and Cl- ions will simply be hydrated, as will the K+ and OH- ions. No precipitate nor gas will form, so there will be no reaction.
For the other reactions, you would have:
(A) Al2O3(s) + 2KOH(aq) ==> 2KAlO2(aq) + H2O(l) at high temperature
(B) CuSO4(aq) + 2KOH(aq) ==> Cu(OH)2(s) + K2SO4(aq)
(D). Na2SO4(aq) + KOH(aq) ==> no reaction because no precipitate nor any gas is formed.
Stanton D.
One could think of Al as present as KAlO2, hydrated, but the likely aluminum species is better described as Al(OH)4, single negative charge. Nothing forces water to disproportionate to O(2-) if it doesn't need to, hence (OH)- are the ligands. It's a little tricky to say that no reaction occurred for C: You would have trouble recovering solid NH4Cl, I think; the characteristic association of NH4+ and Cl- has been altered! So the single choice would be (D) - no change to any ions present.12/29/19
J.R. S.
12/29/19
Nwosu S.
Sir J. R. S. I really like your answer Because Aluminum oxide is amphoteric oxide which when reacts with alkaline (KOH) gives complex salt. And when reacted with the sulphate solutions products occur by displacement reaction. With Solid NH4CL which must be made solution by adding water, which will lead to ion dissociation. NH4+ And CL- Therefore it is saturated moving as ions thereby increases the conductivity of the solution. If KOH is added no reaction instead ions will be moving around the solution. Thanks and that's my suggestion.12/31/19
Joseph A.
I edited it i meant by no. D sodium not solid12/28/19