How many grams of Cu(OH)2 can react with this solution?

Question

132 g of H2SO4 in solution is 24,5% its mass. How many grams of Cu(OH)2 can react with this solution?

Cu(OH)2 (s) + H2SO4 (aq) -> CuSO4 (aq) + 2H2O (l)

Answer 1

Cu(OH)₂ (s) + H₂SO₄ (aq) -> CuSO₄ (aq) + 2H₂O (l) ... balanced equation

If the H₂SO₄ solution is 24.5% by mass, and there are 132 g of this solution, we find the actual grams of H₂SO₄ as follows:

132 g soln x 0.245 = 32.34 g H₂SO₄

The balanced equation tells that that 1 mole Cu(OH)₂ will react with 1 mole H₂SO₄. So, we now need to find moles H₂SO₄ present, and then moles of Cu(OH)₂ and finally grams of Cu(OH)₂. This is done as follows:

moles H₂SO₄ = 32.34 g H₂SO₄ x 1 mole H₂SO₄/98.08 g = 0.3297 moles H₂SO₄

moles Cu(OH)₂ that will react with 0.3297 moles H₂SO₄:

0.3297 moles H₂SO₄ x 1 mole Cu(OH)₂ / mole H₂SO₄ = 0.3297 moles Cu(OH)₂

grams Cu(OH)₂ = 0.3297 mols Cu(OH)₂ x 97.56 g/mole = 32.17 g = 32.2 g Cu(OH)₂