trigonometry functions

Question

if f(x)=cos²x and g(x)=sin²x, what is (f+g)(pie/16)?

Answer 1

if f(x) = cos²(x) and g(x) = sin²(x) , to find (f+g)(x), we would do: f(x) + g(x) ➝ cos²(x) + sin²(x). Since x = π/16 in this case, the solution would be the sum of:

cos²(π/16)+ sin²(π/16).

However, as the poster above me stated, we can bypass the approximate values of each, sin and cos output, by using the trig identity:

cos²(x) + sin²(x) = 1

Therefore, it doesn’t matter what the x input is for this specific problem. And hence,

cos²(π/16)+ sin²(π/16) = 1

Answer 2

cos² x + sin² x = 1, for all values of x including π/8