J.R. S. answered 12/20/19
Ph.D. University Professor with 10+ years Tutoring Experience
1.6 g x 1 mol/16 g = 0.1 moles
0.1 mol/ 2 min = 0.05 mol/min
So rate of disappearance would be -0.05 mol/min.
Alice S.
asked 12/19/19CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
The molar mass of CH4 is 16 g/mol, and in this reaction, 1.6 g of CH4 is consumed in 2 minutes.
What is rate of disappearance of CH4, given in mol/min?
J.R. S. answered 12/20/19
Ph.D. University Professor with 10+ years Tutoring Experience
1.6 g x 1 mol/16 g = 0.1 moles
0.1 mol/ 2 min = 0.05 mol/min
So rate of disappearance would be -0.05 mol/min.
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