The measure of one acute angle is 3 times the sum of the measure of the other acute angle and 8.

Answer 1

The problem statement seems incomplete, but let's at least write the equation for what is given.

There are 2 acute angles---let's call them A and B. Parsing the sentence, we have:

A = 3( B + 8 )

Is this maybe for a right triangle?? If so, we would know that A + B = 90. That would give us 2 equations, which we could solve for A and B

Answer 2

3x+8<90°...............

Answer 3

B= 3(A+8) = 3A+24

A<90, B<90 as they're acute angles

180>C>90 as it's perhaps implicitly obtuse

A+B+C=180

IF C were near 90, slightly more, then A+B=90 or slightly less

Then A+3A+24= 90 4A=66 A=16.5 B=90-16.5=73.5

IF C were near 180, slightly less, then A+B=0 or slightly > 0

Then A+3A+24 =0 4A=-24 which makes A negative and impossible.

So, C can't be that close to 180 4A+24 has to equal more than 24, so C < 180-24 or 156

90<C<156 IF C<156, but close to 156, then A is slightly greater than 0 and B is slightly greater than 24

0<A<16.5

24<B<73.5

90<C<156

That is, assuming the number 8 means 8 degrees and not radians. But it can't mean radians, as 8 radians is greater than 2pi.

There is no unique solution, but you can narrow down the range of possibilities, and C>B>A.

But check with other answers, they may see something more in this problem. Or maybe, just maybe

you left out part of the problem? You have basically 2 equations 3 unknowns, leaving an infinite number of solutions. Did this problem come with a diagram? a graph? You seem to need some additional information to get a unique solution. But if C is not obtuse, then C could also be acute, and 0<C<180,

About all you could say is B>A. C could be an angle <, > or in between both A and B

If 0<C<180, where C is either acute, oblique or obtuse,

then if C is near 0, A+B is near 180. B=3A+24, so A+3A+24 = almost 180

4A=180-24=156

A=156/4=39, but then B=3A+24=117+24=141 which

is not possible, since B is acute and <90

3A+24<90, so 3A<90-24=66 and A<22. then B<90

IF 0<C<180, then B<90 and A<22, when all 3 angles could be acute