I need help finding CosØ

Question

Find Ø for 0°< Ø < 360°

Cosø=0.5972

Answer 1

First of all, cosine is positive where x-values are positive, which is in quadrants I and IV. So we are looking for two answers here.

We are looking for an angle that has a cosine of 0.5972. When we want to find an angle, we use an inverse trig function! In a calculator, perform cos^-1(0.5972) ≈ 53.33°. This is the angle in Quadrant I. To find the second solution from Quadrant IV, take 360° - 53.33° = 306.67°.

So the two solutions are ≈53.33° and ≈306.67°

Answer 2

According to my calculator:

53.33°