What is a 3-digit number whose 3rd digit is 4 times the 1st digit, and whose middle digit is less than the other two digits

Answer 1

Let the number be ABC

C = 4A B<A and B<C

A can only be 1 or 2 because if it is 3 or greater, 4A is 2 digits otherwise.

A can't be 0 because 4A = 0 yielding B is not < A.

Then A has to be 1 and c = 4, with B<A, B = 0.

So the number is 104.

Answer 2

To me, the quickest way out of this one is trial and error...

How many options are there for a pair of digits with a ratio of 4?

1 X 4

2 X 8

Hopefully, you can look at this short list and see your answer.....