The ksp for BaF2 is 1.7 x 10^-6 . What is the concentration of Ba+2 in a saturated solution of BaF2?

Answer 1

BaF₂(s) <===> Ba²⁺(aq) + 2F^-(aq)

Ksp = [Ba²⁺][F^-]²

Let x = [Ba²⁺] and then [F^-] = 2x

1.7x10^-6 = (x)(2x)²

1.7x10^-6 = (x)(4x²)

1.7x10^-6 = 4x³

x³ = 4.25x10^-7

x = 7.52x10^-3 M = [Ba²⁺]