J.R. S. answered 12/16/19
Ph.D. University Professor with 10+ years Tutoring Experience
Look at the correctly balanced equation for this neutralization reaction:
H2SO4(aq) + 2NaOH(aq) ==> Na2SO4(aq) + 2H2O(l)
1). Calculate moles of H2SO4 present:
100.0 ml x 1 L/1000 ml x 0.2000 mol/L = 0.02 moles H2SO4
2). Calculate moles of NaOH needed to react with 0.02 moles H2SO4
0.0 2 moles H2SO4 x 2 moles NaOH/mol H2SO4 = 0.04 moles NaOH needed
3). Calculate volume of 4.00 M NaOH needed:
(x L)(4.00 moles NaOH/L) = 0.04 moles NaOH
x = 0.01 L x 1000 mls/L = 10.0 mls NaOH needed (3 significant figures bases on 3 s.f. in 4.00 M)