
Johannah I. answered 12/19/19
Experienced Math Tutor
The null hypothesis is p=0.15
The alternative hypothesis is p<0.15
The test statistic is -3.827. This can be calculated using a 1-PropZTest.
The p-value for the problem is 0.00006.
At both the 0.01 and 0.05 level, there is sufficient evidence to support the claim that less than 15% of US adults have a great deal of confidence in banks. This can be determined using the p-value:
If p<α then reject the null
If p>α then fail to reject the null
It can also be determined using the test statistic.
If the test statistic for a left-tailed test is less than the z score for each given α then then null hypothesis is rejected
If the test statistic for a left tailed test is greater than the z score for each given α then fail to reject the null hypothesis.