Two events A and B are independent if P(A and B) = P(A)P(B)
Let A = the first toss is tails and B = the second toss is heads
P(A) = 1/2
P(B) = 1/2
P(A)P(B) = (1/2)(1/2) = 1/4
The possibilities for two coin tosses are: HH, TT, HT, TH
So, P(A and B) = 1/4
Therefore, P(A and B) = P(A)P(B). So, A and B are independent events.
Keilly M.
A) P(A and B) = 1/4+1/4 Eliminate B) P(A and B) = 1/4-1/4 C) P(A and B) = 1/2x1/2 D) P(A and B) = 1/2x1/4 those were the answer choices12/14/19