Oli S.

asked • 12/13/19

Let theta be an angle in quadrant II

Let theta be an angle in quadrant II such that tan theta = -3/4. Find the exact values of cos theta and csc theta

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Patrick B. answered • 12/13/19

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tangent = opposite /. adjacent = -3/4 in quadrant 2


x=-3 and y=4, which forces hypotenuse to be 5 by pythagorean


sine is positive and cosine is negative in 2nd quadrant

cosine is -3/5 and sine is 4/5.

secanat is -5/3 and cosecant is 5/4

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LEV K.

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That is an excelent and effective GEOMETRIC solution. If, on the other hand, you need to show TRIGONOMETRIC solution - it will be more complex
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12/13/19

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