Keep in mind that the sin function (y/r) is positive in the 1st and 2nd quadrants where y is positive.
Carla J.
asked • 12/13/19Solve sin x =√2/2 for 0 ≤ x < 2π (round to the nearest hundredth of a radian).
I received the answers π/4 (45 degrees) and 3π/4 (135 degrees). I have no idea what quadrant the two values would fall in. Solve sin x =√2/2 for 0 ≤ x < 2π (round to the nearest hundredth of a radian).
More
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Carla J.
Are my answers π/4 (45 degrees) and 3π/4 (135 degrees) correct? Do I need to go back and make revisions? Also, How would I place the answers into the quadrants, would I use the trig circle? Thank you!12/13/19