Michael H. answered 12/12/19
High School Math, Physics, Computer Science & SAT/GRE/AP/PRAXIS Prep
It is easier to compute the probability of picking 0 or 1 boys, then subtracting from 1.
Let P(x) = probability of picking x boys and the rest girls.
P(0) = (8 / 14) (7 / 13) (6 / 12) (5 / 11) (4 / 10) (3 / 9)
Let C(n,k) = the number of ways k elements can be chosen from among n elements. Same as Combinations.
C(n,k) = n! / (n-k)!
C(6,1) = 6! / 5! = 6 * 5! / 5! = 6
P(1) = 6 * (6 / 14) (8 / 13) (7 / 12) (6 / 11) ( 5 / 10) ( 4 / 9 )
The solution is 1 - P(0) - P(1) = 0.8135