For 12.4g of liquid SO2Cl2 obtained from the reaction of 6.11g of gaseous SO2 and excess gaseous Cl2, calculate the percent yield.

Question

Step by step how to solve and get the percent yield

Answer 1

SO₂ + Cl₂ ==> SO₂Cl₂

6.11 g SO₂ x 1 mol SO₂/64.1 g x 1 mol SO₂Cl₂ / mol SO₂ x 135.0 g/mol SO₂Cl₂ = 12.87 g SO₂Cl₂ theoretical yield

percent yield = actual/theoretical (x100) = 12.4 g/12.87 g (x100) = 96.3% yield