Property of Binomial Distribution
Directions: Find each specified probability for the given scenario.
Suppose that the probability of Thad making a free throw in the championship basketball game is 60% and each throw is independent of his last throw. Assume that Thad attempts seven free throws during the game.
a.) What is the probability that he will make more than four of his three throws?
b.) What is the probability that he will make all of his free throws?
More
1 Expert Answer
Johannah I. answered • 12/18/19
Tutor
5
(3)
Experienced Math Tutor
Part B requires you to calculate P(X=7). This too can be calculated by hand using the binomial probability formula in which n=7, p=0.60, and x=7. It can also be calculated using the binompdf function on the calculator: binompdf(7,0.60,7)
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Johannah I.
To determine the probability of making more than 4 of his free throws, you need to calculate: P(X=5)+P(X=6)+P(X=7). Each of these binomial probabilities can be calculated using: nCx(p)^x(1-p)^(n-x) n is the number of trials x is the number of successes p is the probability C is the combination function Using a TI-84 (or similar) calculator, you can also calculate each of these binomial probabilities and find their sum using the binompdf function (in the DISTR menu): binompdf(7,0.60,5)+binompdf(7,0.60,6)+binompdf(7,0.60,7) Alternatively, you solve this problem by evaluating 1-P(X less than or equal to 4). In order to do so, use the binomcdf function (in the DISTR menu). The binomcdf function is used (as opposed to pdf) because we want to determine a cumulative probability up to X=4. 1-binomcdf(7,0.60,4) All methods will yield the same probability.12/18/19