Help me to set this equation up

Question

Assume you have a 100g sample, you can change the % symbols to grams.

what is the empirical formula of a compound with the following composition:

44.33% oxygen

41.17% chromium

14,50% manganese

empirical formula?

name of compound?

Answer 1

Step 1: convert all percentages into grams and find moles present

44.33 g O / 15.999 (g/mol) = 2.77079817488593 mol

41.17 g Cr / 51.9961 (g/mol)= 0.7917901534922812 mol

14.50 g Mn / 54.938044 (g/mol) = 0.2639336777261309 mol

Step 2: divide by least amount of moles to get ratio

2.77079817488593 mol of O/0.2639336777261309 = 10.49808496875882

0.7917901534922812 mol of Cr/0.2639336777261309 = 2.999958778712117

0.2639336777261309 mol of Mn/0.2639336777261309 = 1

Step 3 round and plug into empirical formula

(rearrange based on C first, then H, then the rest in alphabetical order)

Cr₃MnO₁₀

Pretty sure that the molecule is made up because I don't know how to name it other than

Trichromium Monomanganese Decoxide if that's what you're looking for.