Partial pressure question

Question

A 8.90 L container holds a mixture of 2 gases at 25 degree C. The Partial pressure of gas A and gas B, respectively, are .328 atm and .758 atm. If .180 miles of the 3rd gas is added with no change of volume and pressure, what will the total pressure become?

Answer 1

If a third gas is added and there is no change in volume and no change in pressure, this suggests a change in temperature. But that's not what the question is asking. So, since the question states that the PRESSURE does not change upon addition of 0.18 moles of a 3rd gas, the total pressure will be the sum of the pressures of the 2 original gases.

Total pressure = 0.328 atm + 0.758 atm = 1.086 atm