J.R. S. answered 12/09/19
Ph.D. University Professor with 10+ years Tutoring Experience
2N2O(g) + O2(g) ==> 4NO(g) ... balanced equation
You provide values of +82 and +90 kJ/mol, but you don't state what those values are. Are they ∆Hºf? Assuming they are, proceed as follows:
∑∆Hfproducts - ∑∆Hfreactants = ∆Hrxn
(4x90) - (2x82) = 360 - 164 = ∆Hrxn
∆Hrxn = +196 kJ when 2 mol N2O reacts
∆Hrxn/mole = 196/2 = +98 kJ/mol