How many mL of 0.200M Ca(OH)2 are required to neutralize 50.0mL of 0.500M HNO3

Answer 1

Write the balanced equation:

Ca(OH)₂ + 2HNO₃ ==> Ca(NO₃)₂ + 2H₂O

moles HNO3 present = 50.0 ml x 1 L/1000 ml x 0.500 mol/L = 0.0250 moles

moles Ca(OH)₂ needed = 0.0250 mol HNO₃ x 1 mol Ca(OH)₂ / 2 mol HNO₃ = 0.0125 moles

volume of Ca(OH)₂ needed: (x L)(0.200 mol/L) = 0.0125 moles

x = 0.0625 L

x = 62.5 mls