Find the distance from p to l. Line l contains points (6,5) and (2,3). Point p has coordinates (2,6).

Answer 1

The equation of the line is 1/2 =(y-3)/(x-5) i.e. x-2y+1=0

The distance involved is (2-12+1)/sqrt(1+4).

The distance d from a point (x₀,y₀) to a line Ax+By+c is given by

d=(Ax₀+By₀+C)/sqrt(A² + B²⁾