The specific heat of a certain type of cooking oil is 1.75 J / ( g ⋅ ° C ) . How much heat energy is needed to raise the temperature of 2.24 kg of this oil from 23 ° C to 191 ° C?

Answer 1

We use the formula q = mC∆T

q = heat = ?

m = mass = 2.24 kg x 1000 g/kg = 2240 g

C = specific heat = 1.75 J/g/deg

∆T = change in temperature = 191º - 23º = 168ºC

q = (2240 g)(1.75 J/g/deg)(168 deg) = 658,560 J = 659 kJ