In △ABC, m∠A=α, m∠B=β, m∠C=γ. AB=c, AC=b, BC=a. Find the remaining parts of each triangle if the following parts are given. a=45.7, α=65º, β=49º

Answer 1

a/sinα=b/sinβ=c/sinγ

45.7/.906=50.42=b/.755; b=38.07

α+β+γ=180º

65+49-180 so γ=66º

c/.913=50.42; c=46.06