How many grams of water will the organism produce if it needs 6000.kJ to survive?

Question

Balanced equation:

4 FESO4 + 2 H2SO4 + O2 ----> 2 Fe2(SO4)3 + 2 H20

  -929        -735             -2583      -286

Answer 1

4FeSO₄ + 2H₂SO₄ + O₂ ===> 2Fe₂(SO₄)₃ + 2H₂O

Assuming that the values provided in the original problem are in kJ...and that they are ∆Hf values....

∆Hrxn = [-(2x2583 + -286)] - [4(-929) + 2(-735)] = -5452 - (-5186) = -266 kJ (this is for 2 moles H₂O)

6000 kJ x 2 mol H₂O/266 kJ x 18 g/mole = 812 g H₂O needed