J.R. S. answered 12/03/19
Ph.D. University Professor with 10+ years Tutoring Experience
The maximum number of hydrogens in a 2 carbon molecule is 6 (2n + 2). Thus, the compound would be C2H6.
Combustion of C2H6:
2C2H6(g) + 7O2(g) ===> 4CO2(g) + 6H2O(l)
moles of C2H6 = 72 g x 1 mol/30 g = 2.4 moles
moles of liquid water produced = 2.4 moles C2H6 x 6 moles H2O/2 moles C2H6 = 7.2 moles H2O(l)