What is the equation of the line perpendicular to y=1/2x+1 that contains the point (-2,1)?

Answer 1

The line perpendicular to this one will have a slope equal to the negative reciprocal. In the equation provided, the slope is 1/2. So m=-2 for the line perpendicular. Then you can use the following equation. (y-y1)=m(x-x1)

Plug in the values of (x1,y1) using the point provided. (-2,1)

(y-1)=-2(x-(-2)) Simplify

(y-1)=-2(x+2)Distribute

y-1=-2x-4 Add 1 to both sides

y-1+1=-2x-4+1 Simplify

y=-2x-3