Joie T.

asked • 12d

A 2.11 g sample of acetylsalicylic acid required 23.29 mL of 0.5028 M NaOH for complete reaction. Find the molar mass (in g/mol) of acetylsalicylic acid and its Ka value.

The active ingredient in aspirin is acetylsalicylic acid. A 2.11 g sample of acetylsalicylic acid required 23.29 mL of 0.5028 M NaOH for complete reaction. Addition of 13.08 mL of 0.4476 M HCl to the flask containing the aspirin and the sodium hydroxide produced a mixture with pH = 3.48. Find the molar mass (in g/mol) of acetylsalicylic acid and its Ka value. Acetylsalicylic acid is a monoprotic acid.


molar mass ________ g/mol


Ka _______

1 Expert Answer

By:

J.R. S. answered • 12d

Ph.D. University Professor with 10+ years Tutoring Experience

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