J.R. S. answered 11/30/19
Ph.D. University Professor with 10+ years Tutoring Experience
qrxn = q(cal) + q(H2O)
qrxn = Ccal x ∆T + mC∆T
qrxn = (784 J/deg x 8.39 deg) + (925 g x 4.184 J/g/deg x 8.39 deg)
qrxn = 6578 J + 32,471 J
qrxn = 39,049 J = 39.049 kJ This is the heat produced by the combustion of 0963 g benzene. The question asked how much heat was produced by the combustion of glucose. That answer I don't know. Maybe you should review the question and see what is really being asked.
Catherine S.
Thanks this was very helpful!11/30/19