J.R. S. answered 11/30/19
Ph.D. University Professor with 10+ years Tutoring Experience
You need to look up the pKa for each acid, and to make a pH 2 buffer, choose the acid that has a pKa closest to 2. For example, and as a way of showing how to do the calculations, say you find the Ka HOCl = 3.5 x 10-8 and Ka HF = 6.3 x 10-4. You can calculate the pKa HOCl to be 7.5 and the pKa HF to be 3.2. In this case HF would be a better choice. Do the same for the other acid that are given as choices and see if any has a pKa closer to 2 than HF.
To make 1.0 L of the chosen buffer with pH = 2, use the Henderson Hasselbalch equation to find the ratio of conjugate base to acid. Thus, pH = pKa + log [conjugate base]/[acid]
2.0 = pKa + log [conjugate base]/[acid] and substitute in the value of the pKa for the chosen acid.
Solve for [conjugate base]/[acid]
Then use the appropriate number of moles of each to attain that molar ratio. Done.
J.R. S.
12/01/19
Joie T.
Thank you for your response! I've found that out of the choices I was given the acid is HClO2-. However I cannot figure out how to make 1.0 L of this buffer. This is what I have currently. pH = pKa + log [conjugate base]/[acid] 2.0 = pKa + log [conjugate base]/[acid] 2.0 = 1.96 + log [conjugate base]/[acid] 0.04 = log [conjugate base]/[acid] e^(0.04) = e^(log [conjugate base]/[acid]) 1.040810774 = [conjugate base]/[acid] I do not know how to use the appropriate number of moles of each to attain that molar ratio. Please help :((12/01/19