Joie T.

asked • 11/30/19

Which acid would be the best choice for preparing a pH = 2.00 buffer? How would you prepare 1.0 L of this buffer?

(a) Which acid would be the best choice for preparing a pH = 2.00 buffer?

HClO2

HOCl    

HC2H3O2

HCN

HF


How would you use Ka values to calculate this?? Please show the steps.


(b)

Explain how to make 1.0 L of this buffer.

To prepare this buffer, add conjugate base and weak acid in the concentration ratio of ______ parts conjugate base : 1 part weak acid.


How do you use the Ka to find out the ratio of parts?

1 Expert Answer

By:

Joie T.

Thank you for your response! I've found that out of the choices I was given the acid is HClO2-. However I cannot figure out how to make 1.0 L of this buffer. This is what I have currently. pH = pKa + log [conjugate base]/[acid] 2.0 = pKa + log [conjugate base]/[acid] 2.0 = 1.96 + log [conjugate base]/[acid] 0.04 = log [conjugate base]/[acid] e^(0.04) = e^(log [conjugate base]/[acid]) 1.040810774 = [conjugate base]/[acid] I do not know how to use the appropriate number of moles of each to attain that molar ratio. Please help :((
Report

12/01/19

J.R. S.

tutor
2.0 = 1.96 log [conj.base]/[acid] log [conj.base]//[acid] = 0.04 [conj.base]/[acid] = 1.096 (looks like you did natural antilog instead of antilog base 10). Now, to make the buffer with the desired ratio, you must first choose a concentration, e.g. 0.1 M. Then proceed as follows: If the conjugate base is to be 0.1M, then find the [acid]... 0.1 / x = 1.096 x = 0.0912 = moles acid So, to make this buffer you would add 0.1 mole of ClO2^- (perhaps as the sodium salt), and 0.0912 moles of HClO2 to a final volume of 1 liter. Hope this makes sense, and hope it helps.
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12/01/19

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