Tom N. answered 11/30/19
Strong proficiency in elementary and advanced mathematics
Let x=r cosθ and y=r sinθ put these into the equation to get (r cosθ -1)2 +( r sinθ +1)2 = 2 which gives r2 cos2θ -2r cosθ +1 +r2 sin2θ +2 r sinθ +1 =2 r2( cos2θ +sin2θ) -2r cosθ +2r sinθ +2 =2 so r2 -2r cosθ +2r sinθ =0 and r -2cosθ +2 sinθ =0.