J.R. S. answered 11/26/19
Ph.D. University Professor with 10+ years Tutoring Experience
The approach to this problem will depend to a large extent on the table of thermodynamic values that are provided/available. Also, the question makes little sense because you can't really have a "standard cell potential" at 80ºC since the standard cell potential is defined at 25ºC or 298K.
Cu2+ + 2e- ==> Cu Eº = +0.34V ... anode = oxidation
Ag+ + e- ==> Ag Eº = +0.8V ... cathode = reduction
2Ag+ + Cu ==> 2 Ag + Cu2+ ... overall reaction and transfer of 2 moles electrons
Depending on what the question is really asking, and assuming values of ∆G are provided, one could use
∆Gº = -RT ln K to find K and then use Eº = RT/nF ln K. But note that the conditions would be 1 M of Cu2+ and Ag+ but the temperature of 80ºC is not standard.